7th Class Mathematics Practical Geometry Question Bank

done Practical Geometry Total Questions - 13

• question_answer1)
  In \[\Delta ABC,\]if \[AB=7\text{ }cm,\text{ }\angle A={{40}^{o}}\]and \[\angle B={{70}^{o}}\],which criterion can be used to construct this triangle?                
  A)
   ASA                done clear
  B)
   SSS                done clear
  C)
          SAS    done clear
  D)
          RHS done clear
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• question_answer2)
  Which one of the following is true for the given triangle?           
  A)
   \[\angle 3=\angle 1+\angle 2\] done clear
  B)
   \[\angle 1=\angle 3+\angle 2\] done clear
  C)
   \[\angle 2=\angle 1+\angle 3\] done clear
  D)
   Both (a) and (b) done clear
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• question_answer3)
  The __ criterion is used to construct a triangle when the lengths of the three sides are given.                            
  A)
   SAS                done clear
  B)
   SSS                done clear
  C)
   RHS   done clear
  D)
                                  ASA done clear
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• question_answer4)
  A triangle can be constructed by taking its sides as                              
  A)
   \[1.8\text{ }cm,\text{ }2.6\text{ }cm,\text{ }4.4\text{ }cm\]            done clear
  B)
   \[2\text{ }cm,\text{ }3\text{ }cm,\text{ }4\text{ }cm\]       done clear
  C)
   \[2.4\text{ }cm,\text{ }2.4\text{ }cm,\text{ }6.4\text{ }cm\]            done clear
  D)
   \[3.2\text{ }cm,\text{ }2.3\text{ }cm,\text{ }5.5\text{ }cm\]            done clear
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• question_answer5)
  A triangle can be constructed by taking two of its angles as                    
  A)
   \[{{110}^{o}},\text{ }{{40}^{o}}\]         done clear
  B)
  \[{{70}^{o}},{{115}^{o}}\]     done clear
  C)
                      \[{{135}^{o}},{{45}^{o}}\]       done clear
  D)
         \[{{90}^{o}},{{90}^{o}}\]      done clear
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• question_answer6)
  Which of the following sets of triangles could be the lengths of the sides of a right-angled triangle?
  A)
   \[3\text{ }cm,\text{ }4\text{ }cm,\text{ }6\text{ }cm\] done clear
  B)
   \[9\text{ }cm,\text{ }16\text{ }cm,\text{ }26\text{ }cm\] done clear
  C)
   \[1.5\text{ }cm,\text{ }3.6\text{ }cm,\text{ }3.9\text{ }cm\] done clear
  D)
   \[7\text{ }cm,\text{ }24\text{ }cm,\text{ }26\text{ }cm\] done clear
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• question_answer7)
  In which of the following cases, a unique triangle can be drawn?
  A)
   \[AB=4\text{ }cm,\text{ }BC=8\text{ }cm\]and \[CA=2\text{ }cm\] done clear
  B)
   \[BC=5.2\text{ }cm,\text{ }\angle S={{90}^{o}}\]and \[\angle C={{110}^{o}}\] done clear
  C)
   \[XY=5\text{ }cm,\text{ }\angle X={{45}^{o}}\]and \[\angle Y={{60}^{o}}\] done clear
  D)
   An isosceles triangle with the length of each equal side 6.2 cm. done clear
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• question_answer8)
  Which of the following statements is INCORRECT?
  A)
   If length of any two sides of a triangle are 7 cm and 10 cm, then length of its third side lies between 3 cm and 17 cm. done clear
  B)
   It is possible to construct a unique triangle if all its three angles are given. done clear
  C)
   An angle of \[\left( 7\frac{{{1}^{o}}}{2} \right)\] can't be constructed using compasses and ruler. done clear
  D)
   None of these done clear
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• question_answer9)
  Which of the following steps is INCORRECT while constructing \[\Delta XYZ\]if it is given that \[XY=6cm,\angle ZXy={{30}^{o}}\]and \[\angle XYZ={{100}^{o}}\]

  Step 1: Draw line XV of length 6 cm.

  Step 2: At X, draw a ray XP making an angle of \[{{30}^{o}}\]with XY.

  Step 3: At V, draw a ray YQ making an angle of \[{{100}^{o}}\] with YX.

  Step 4: The point of intersection of the two rays XY and YQ is Z.

  A)
   Step 1                         done clear
  B)
   Step 2 and Step 4       done clear
  C)
   Step 3             done clear
  D)
          Step 4 done clear
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• question_answer10)
  Arrange the given steps in CORRECT order, while constructing \[\Delta \,PQR\]where \[PM\bot QS\]and it is given that \[QR=4.2\text{ }cm,\]\[\angle Q={{120}^{o}}\] and \[PQ=3.5\text{ }cm.\]

  Step 1. Now, extend RQ to S and with P as centre and with a sufficient radius, draw an arc, cutting SO at A and 8.

  Step 2. Along QX, set off \[QP=3.5\text{ }cm.\]

  Step 3. Draw a line segment \[QR=4.2\text{ }cm\]and construct\[\angle RQX={{120}^{o}}\].

  Step 4. Joint PR.

  Step 5. Joint PC, meeting RQ product at

  M. Then. \[PM\bot QS\]

  Step 6. With A as centre and radius more than half AB, draw an arc. Now with B as centre and with the same radius draw another arc, cutting the previous arc at C.

  A)
   1\[\to \]2\[\to \]3\[\to \]4\[\to \]5\[\to \]6 done clear
  B)
   4\[\to \]1\[\to \]2\[\to \]3\[\to \]5\[\to \]6           done clear
  C)
   2\[\to \]4\[\to \]3\[\to \]1\[\to \]5\[\to \]6           done clear
  D)
   3\[\to \]2\[\to \]4\[\to \]1\[\to \]6\[\to \]5           done clear
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• question_answer11)
  State 'T' for true and 'F' for false.

  (1) In a triangle, the measure of exterior angle is equal to the sum of the measure of interior opposite angles.

  (2) The sum of the measures of the three angles of a triangle is\[{{90}^{o}}\].

  (3) A perpendicular is always at \[{{90}^{o}}\] to a given line or surface.

  A)

  (1)	(2)	(3)
  T	T	F

                  done clear
  B)

  (1)	(2)	(3)
  T	F	F

                  done clear
  C)

  (1)	(2)	(3)
  T	F	T

                  done clear
  D)

  (1)	(2)	(3)
  F	T	F

  done clear
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• question_answer12)
  Which of the following steps is INCORRECT while constructing \[\Delta LMA,\]right angled at M, given that \[LN=5\text{ }cm\]and\[MN=3\text{ }cm\]?

  Step 1. Draw MN of length 3 cm.

  Step 2. At M, draw MX1MN. (L should be somewhere on this perpendicular).

  Step 3. With N as centre, draw an arc of radius 5 cm. (L must be on this arc, since it is at a distance of 5 cm from N).

  Step 4. L has to be on the perpendicular line MX as well as on the arc drawn with centre N. Therefore, L is the meeting point of these two and ALMA/ is obtained.

  A)
   Only Step 4 done clear
  B)
   Both Step 2 and Step 3 done clear
  C)
   Only Step 2 done clear
  D)
   None of these done clear
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• question_answer13)
  Arrange the steps marked (i) to (v) In CORRECT order while constructing a line parallel to a given line, through a point not on the line using ruler and compasses only.

  Step 1. Take a line 'l' and a point ?A? outside ?l?.

  Step 2. Take any point Son l and join 8 to A

  (i) Now with A as centre and the same radius as in previous step, draw an arc EF cutting AB at G.

  (ii) With the same opening as in previous step and with G as centre, draw an arc cutting the arc EF at H.

  (iii) With B as centre and a convenient radius, draw an arc cutting l at C and BA at D,

  (iv) Now, join AH to draw a line W.

  A)
   (i)\[\to \](ii)\[\to \](iv)\[\to \](iii) done clear
  B)
   (iii)\[\to \](i)\[\to \](ii)\[\to \](iv) done clear
  C)
   (iii)\[\to \](ii)\[\to \](i)\[\to \](iv) done clear
  D)
   (i)\[\to \](ii)\[\to \](iii)\[\to \](iv) done clear
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