9th Class Science Force and laws of motion Question Bank 9th CBSE Science Force and laws of motion

  • question_answer
    The velocity-time graph of a ball moving on the surface of floor is shown in figure. Calculate the force acting on the ball if mass of the ball is 100 g.

    Answer:

                                                    The velocity time graph shows that the velocity of the ball at t = 0 is zero. Initial velocity of ball, u = 0. Velocity of ball at t = 4 s is 20 \[\text{m}{{\text{s}}^{\text{-1}}}\] That is, final velocity, u = 20 \[\text{m}{{\text{s}}^{\text{-1}}}\] Time,             t = 4 s \[\therefore \]Acceleration of the ball, \[a=\frac{\upsilon -u}{t}\] or     \[a=\frac{20\,\text{m}{{\text{s}}^{-1}}-0}{4s}\Rightarrow a=5\,\text{m}{{\text{s}}^{-2}}\]  Also, mass of ball, \[m=100g=\frac{100}{1000}kg=\frac{1}{10}kg\] \[\therefore \]Force acting on the ball, F= ma or\[F=\frac{1}{10}kg\times 5m{{s}^{-2}}\] \[=0.5kgv-m{{s}^{-2}}0.5N[\because 1kg\,m{{s}^{-2}}=1N]\]


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