Answer:
Initially the body was at rest. The linear
momentum of the body is thus p = mu = 0. The body breaks due to internal
forces. As the external force acting on it is zero, its linear momentum will
remain constant, that is, zero.
The momentum of
first part \[{{p}_{1}}={{m}_{1}}{{\upsilon }_{1}}\]
= (200 g)
x(12 m/s), towards the east.
The linear
momentum of the other part must have the same magnitude and should be opposite
in direction. It therefore moves towards the west. If its speed is \[{{\upsilon
}_{2}}\], its linear momentum is \[{{p}_{2}}={{m}_{2}}{{\upsilon
}_{2}}=(100g)\times {{\upsilon }_{2}}\]
Now, \[{{m}_{1}}{{\upsilon
}_{1}}={{m}_{2}}{{\upsilon }_{2}}\]
Thus, \[(200g)\times
(12m/s)=(100g)\times {{\upsilon }_{2}}\]
or\[{{\upsilon
}_{2}}=24\,m/s\]
The velocity of the
other part is 24 m/s towards the west.
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