Answer:
Initial
velocity, u = 20 m/s
Maximum height the ball will reach, h = ?
Using equation v2 = u2 + 2gh
( At maximum height, v = 0)
(1)
This means ball will reach the height of 20 m and comes
back. It will pass the window two times. (1/2)
Now to calculate the time ball will take to reach 15m heights
Using equations,
Thus, ball will pass the window at 1 second and 3 seconds
respectively.
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