A) \[\text{45}{}^\circ \]
B) \[\text{12}0{}^\circ \]
C) \[\text{15}0{}^\circ \]
D) \[\text{6}0{}^\circ \]
Correct Answer: B
Solution :
\[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] By substituting, \[A=F,\ B=F\] and \[R=F\] we get \[\cos \theta =\frac{1}{2}\therefore \theta =120{}^\circ \]You need to login to perform this action.
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