question_answer

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides                                                                                            [JIPMER 2000]

A)                 \[\text{6}0{}^\circ \] equilateral triangle               

B)                 \[\text{12}0{}^\circ \] equilateral triangle 

C)                 \[\text{12}0{}^\circ \], \[\text{3}0{}^\circ \], \[\text{3}0{}^\circ \] an isosceles triangle

D)                 \[\text{12}0{}^\circ \] an obtuse angled triangle

Correct Answer: A

Solution :

                    In N forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given \[\theta =\frac{360}{N}\]\[=\frac{360}{3}=120{}^\circ \] If these three vectors are represented by three sides of triangle then they form equilateral triangle