A) \[\Rightarrow \]
B) \[P(-a)=0\]
C) \[P(x)={{x}^{3}}-3{{x}^{2}}+4x-12\]
D) \[P(x)={{x}^{3}}-3{{x}^{2}}+4x-12\]
Correct Answer: B
Solution :
\[{{x}^{0}}\]\[\frac{{{x}^{5}}-7{{x}^{2}}+18}{{{x}^{3}}-2}\]
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