A) no value of \[x\]
B) all values of \[x\] between - 5 and 6
C) all\[x\]
D) \[x>6\,\,or\,\,x<-5\]
Correct Answer: D
Solution :
\[{{x}^{2}}-x-30={{x}^{2}}-6x+5x-30\] \[=(x+5)(x-6)\] \[\therefore \] \[(x+5)(x-6)>0\] It is positive for \[x>6\] and\[x<-\,\,5\]
You need to login to perform this action.
You will be redirected in
3 sec
