A) 1 and 2 are correct
B) 1, 2 and 3 are correct
C) 2 and 3 are correct
D) 1 and 3 are correct
Correct Answer: A
Solution :
1. Remainder\[={{2}^{3}}-{{3.2}^{2}}+4\times 2-4\] \[=8-12+8-4=0\]. Hence \[x-2\] is a factor. 2. Remainder \[=2{{(-1)}^{3}}+4(-1)+6\] \[=-2-4+6=0\] Hence\[x+1\]is a factor. 3. Remainder\[={{1}^{6}}-{{1}^{5}}+{{1}^{5}}-{{1}^{3}}+{{1}^{2}}-1+1=1\]. Hence \[x-1\] is not a factor. \[\therefore \]Statements 1 and 2 are correct.
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