A) \[f(x)=4x+7\]
B) \[f(x)=x+{{x}^{2}}\]
C) \[f(x)=\cos x\]
D) \[f(x)={{\log }_{e}}x\]
Correct Answer: A
Solution :
If \[f(x)=4x+7\] Then\[\frac{f-f}{a-b}=\frac{(4a+7)-(4b+7)}{a-b}\] \[=\frac{4(a-b)}{(a-b)}\] \[=4\](constant). It is constant for all numbers \[a\] and\[b\], where\[a\ne b\].You need to login to perform this action.
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