6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    Which of the following equations does not have a solution in integers?

    A)  \[x+1=1\]

    B)  \[x-1=3\]

    C)  \[2x+1=6\]

    D)  \[1\text{ }-x=5\]

    Correct Answer: C

    Solution :

    (a) x + 1 = 1
    \[\Rightarrow x+1-1=1-1\]
    [Subtracting 1 from both sides]
    \[\Rightarrow x=0\], which is an integer
    (a) \[x-1=3\]
    \[\Rightarrow x-1+1=3+1\]
    [Adding 1 to both sides]
    \[\Rightarrow x=4\], which is an integer.
    (c) \[2x+1=6\]
    \[\Rightarrow 2x+1-1=6-1\]
    [Subtracting 1 from both sides]
    \[\Rightarrow 2x=5\]
    \[\Rightarrow \frac{2x}{2}=\frac{5}{2}.\] [Dividing both sides by 2]
    \[\Rightarrow x=\frac{5}{2},\] which is not an integer.
    (d) \[1-x=5\]
    \[\Rightarrow 1-x-1=5-1\]
    [Subtracting 1 from both sides]
    \[\Rightarrow -x=4\]
    \[\Rightarrow -(-x)=-4\]
    [Multiplying both sides by (-1)]
    \[\Rightarrow x=-4\], which is an integer.
    Thus, the above conditions show that equation \[2x+1=6\] does not have a solution in integers.


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