A) \[{{x}^{2}}+5x-1=0\]
B) \[{{x}^{2}}-5x-1=0\]
C) \[{{x}^{2}}-5x+1=0\]
D) \[{{x}^{2}}+5x+1=0\]
Correct Answer: A
Solution :
Let\[x=\frac{1}{5+\frac{1}{5+1}}.....\] \[\therefore \] \[x=\frac{1}{5+x}\] or \[5x+{{x}^{2}}=1\] or \[{{x}^{2}}+5x-1=0\]
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