A) \[=x+x+3=2x+3\]
B) \[\frac{11x+3}{2x+3}=\frac{4}{1}\]
C) \[11x+3=8x+12\]
D) \[3x=9\]
Correct Answer: C
Solution :
\[\frac{{{x}^{3}}+2{{x}^{2}}-x}{{{x}^{2}}-9}\] \[\frac{{{x}^{3}}-2{{x}^{2}}+x}{{{x}^{2}}-9}\] \[\frac{x}{2}+10+5\]
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