A) \[\frac{{{x}^{2}}-2}{x-1}\]
B) \[\frac{{{x}^{2}}}{x-1}\]
C) \[\frac{{{x}^{2}}}{x-1}\]
D) \[\frac{2x}{x-1}\]
Correct Answer: C
Solution :
\[(x+1)\,+\frac{1}{x-1}\,=\frac{\left( {{x}^{2}}-1 \right)+1}{x-1}\,=\frac{{{x}^{2}}}{x-1}\]
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