A) \[x+2=0\]
B) \[x=-2\]
C) \[P(x)={{x}^{3}}+{{x}^{2}}+2x+3\]
D) \[P(-2)={{(-2)}^{3}}+{{(-2)}^{2}}+2(-2)+3\]
Correct Answer: D
Solution :
\[{{(a+b)}^{3}}-{{(a-b)}^{3}}=\_\_\_\_\_.\] \[{{b}^{3}}+3{{a}^{2}}b\]You need to login to perform this action.
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