A) 0 and 0
B) 9 and 0
C) 0 and 21
D) 0 and 9
Correct Answer: C
Solution :
Cross-multiplying, we get \[({{a}_{0}}\ne 0)\] \[\Rightarrow \] \[f(x)=ax+b\] \[\Rightarrow \] \[3xy+7x{{y}^{2}}-8x{{y}^{3}}+7{{y}^{2}}{{x}^{2}}\]\[p(x)=3{{x}^{2}}{{y}^{3}}+5x{{y}^{7}}-{{x}^{6}}\] \[\Rightarrow \] \[{{x}^{3}}+{{x}^{2}}-4x+8\] \[\Rightarrow \] \[2{{a}^{2}}-42a=0\] \[\Rightarrow \] \[-1\] \[\Rightarrow \] \[2a=0\] or \[a-21=0\] \[\Rightarrow \] \[a=0\] or \[a=21\]
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