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8th Class Mathematics Algebraic Expressions Question Bank Algebra

  • question_answer
    The present age of a man is 3 times that of his son. Six years ago, the age of the man was four times that of his son. Find the ratio of their ages 6 years later.

    A) 4:3                 

    B) 3:4

    C) 2:5                 

    D) 5:2

    Correct Answer: D

    Solution :

    Let present age of son =x Present age of man = 3x Six years ago: Age of man \[=3x-6\] Age of son \[=x-6\] \[{{x}^{3}}+\frac{1}{{{x}^{3}}}\] \[3x-2=\frac{8}{x}.\] \[\left( -\frac{3}{4},2 \right)\] Six years after: Age of man = \[3\times 18+6=60\] Age of son \[=18+6=24\] Ratio \[=60:24=5:2.\]


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