A) \[10t+u+1\]
B) \[100t+10u+1\]
C) \[t+u+1\]
D) None of these
Correct Answer: C
Solution :
Given \[3x-2=\frac{8}{x}\] Multiplying by x on both sides, we get \[\frac{1}{x}-\frac{3}{4}+\frac{1}{2+x}=0\] \[\Rightarrow \]\[3{{x}^{2}}-2x-8=0\] \[\Rightarrow \] \[3{{x}^{2}}-6x+4x-8=0\] \[\Rightarrow \] \[(-8,0)\] \[\Rightarrow \] \[(x-2)\,(3x+4)=0\] \[\Rightarrow \]\[(x-2)=0\]or \[3x+4=0\] \[\Rightarrow \] \[x=2\] or \[\frac{1}{x}-\frac{3}{4}+\frac{1}{2+x}=0\] \[\left( -\frac{4}{3},2 \right)\] The roots are \[\frac{1}{x}+\frac{1}{2+x}=\frac{3}{4}\]
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