A) \[3a+2b+4c\]
B) \[2a-2b+4c\]
C) \[3a-4b-2c\]
D) \[2a+3b+4c\]
Correct Answer: D
Solution :
Sum \[=(a+3b-4c)+(4a-b+9c)+\]\[(-2b+3c-a)\] \[=(a+4a-a)+(3b-b-2b)+(-4c+9c+3c)\] \[=4a+8c\] \[\therefore \] Required difference \[=(4a+8c)-(2a-3b+4c)\] \[=4a+8c-2a+3b-4c=2a+3b+4c\]You need to login to perform this action.
You will be redirected in
3 sec