A) \[\frac{1}{16}+\frac{3}{16}b+\frac{{{b}^{2}}}{16}\]
B) \[\frac{1}{16}+\frac{3}{8}b+\frac{9}{16}{{b}^{2}}\]
C) \[\frac{3}{16}b+\frac{1}{64}+\frac{9}{16}{{b}^{2}}\]
D) \[\frac{1}{4}+\frac{3}{4}b+\frac{9}{16}\]
Correct Answer: B
Solution :
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