A) Reduction of sodium ions
B) Oxidation of sodium ions
C) Reduction of chloride ions
D) Oxidation of chloride ions
Correct Answer: D
Solution :
\[2NaCl\xrightarrow{\text{Electric}\,\text{current}}\underset{\text{Cation}}{\mathop{2N{{a}^{+}}}}\,+\underset{\text{Anion}}{\mathop{2C{{l}^{-}}}}\,\]
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