A) ? 9 seconds
B) \[\frac{5}{3}\]seconds
C) 9 seconds
D) \[-\frac{5}{3}\]seconds
Correct Answer: C
Solution :
\[\frac{ds}{dt}=\]velocity \[=45+22t-3{{t}^{2}}\] When particle will come to rest, then \[v=0\] Þ \[3{{t}^{2}}-22t-45=0\Rightarrow t=9,\,\,\left( \text{since}\,\,\text{t}\ne -\frac{5}{3} \right)\].
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