2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Applications of Derivatives

JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
    A particle moves so that \[S=6+48t-{{t}^{3}}\]. The direction of motion reverses after moving a distance of [Kurukshetra  CEE 1998]

    A)            63

    B)            104

    C)            134

    D)            288

    Correct Answer: C

    Solution :

               \[S=6+48t-{{t}^{3}}\]                    \[v=\frac{dS}{dt}=0+48-3{{t}^{2}}\]                    when direction of motion reverses, \[v=0\]                    \[48-3{{t}^{2}}=0\]\[\Rightarrow \]\[t=-4,\ 4\];                    \[{{(S)}_{4}}=6+192-64\]i.e.,\[S=134\].


You need to login to perform this action.
You will be redirected in 3 sec spinner