A) Is constant
B) Varies as the distance from the axis of x
C) Varies as the distance from the axis of y
D) Varies as the distance of the point from the origin
Correct Answer: C
Solution :
\[\frac{dx}{dt}={{v}_{x}}=a\Rightarrow \frac{{{d}^{2}}x}{d{{t}^{2}}}=0={{a}_{x}}\] \[{{a}_{x}}\]is acceleration in x-axis \[\frac{{{d}^{2}}y}{d{{t}^{2}}}=-b{{a}^{2}}\sin at\Rightarrow {{a}_{y}}=-{{a}^{2}}y\] Hence, \[{{a}_{y}}\]changes as y changes.
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