A) \[b-c\]
B) \[b+c\]
C) \[2b-2c\]
D) \[2\sqrt{{{b}^{2}}+{{c}^{2}}}\]
Correct Answer: D
Solution :
Acceleration in direction of x-axis = \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=-2c\] and acceleration in direction of y-axis = \[\frac{{{d}^{2}}y}{d{{t}^{2}}}=2b\] Resultant acceleration is =\[\sqrt{{{(-2c)}^{2}}+{{(2b)}^{2}}}=2\sqrt{{{b}^{2}}+{{c}^{2}}}\]
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