A) Velocity
B) (Velocity)3/2
C) (Velocity) 3
D) (Velocity)2
Correct Answer: A
Solution :
Given \[s=\sqrt{t}\]. Now \[v=\frac{ds}{dt}=\frac{1}{2\sqrt{t}}\] Also \[a=\frac{dv}{dt}=\frac{-1}{2\times 2{{(t)}^{3/2}}}\]Þ \[a\propto \frac{1}{t\sqrt{t}}\]or \[a\propto {{v}^{3}}\].
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