A) 2 sec
B) 3 sec
C) 4 sec
D) 6 sec
Correct Answer: A
Solution :
\[s=t+6{{t}^{2}}-{{t}^{3}}\] Þ \[\frac{ds}{dt}=1+12t-3{{t}^{2}}\]Þ\[v=5\,cm/\sec \] Þ \[\frac{{{d}^{2}}s}{d{{t}^{2}}}=0\] Þ \[12-6t=0\Rightarrow t=2\].You need to login to perform this action.
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