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JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
    If a particle moves such that the displacement is proportional to the square of the velocity acquired, then its acceleration is                                                     [Kerala (Engg.) 2005]

    A)            Proportion to\[{{s}^{2}}\]

    B)            Proportional to \[1/{{s}^{2}}\]

    C)            Proportional to s

    D)            Proportional to \[1/s\]

    E)            A constant

    Correct Answer: E

    Solution :

               If displacement \[\propto \] (velocity)2 \[s\propto {{v}^{2}}\]\[\Rightarrow \,\,{{v}^{2}}=2as\].                    Hence a is constant.


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