A) \[9c{{m}^{2}}\]
B) \[4c{{m}^{2}}\]
C) \[23c{{m}^{2}}\]
D) \[36c{{m}^{2}}\]
Correct Answer: C
Solution :
Area of rectangle ABCD = \[\left( 5+4 \right)\times \left( 3+1 \right)=9\times 4=36c{{m}^{2}}\] Area of triangle\[X=\frac{1}{2}\times 4\times 2=4c{{m}^{2}}\] Area of square y \[=3\times 3=9c{{m}^{2}}.\] \[\therefore \] Shaded area= area of ABCD - area of X - area of Y \[=36-4-9=23c{{m}^{2}}.\]
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