A) 1/3
B) 2/3
C) 4/3
D) 8/3
Correct Answer: D
Solution :
Given parabolas are \[{{x}^{2}}=1+y\], \[{{x}^{2}}=1-y\] Required area \[=4\int_{0}^{1}{(1-{{x}^{2}})\,dx}\]\[=4\left[ x-\frac{{{x}^{3}}}{3} \right]_{0}^{1}=\frac{8}{3}\].You need to login to perform this action.
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