A) \[\frac{4\sqrt{2}}{3}sq.\,unit\]
B) \[\frac{28\sqrt{2}}{3}sq.\,unit\]
C) \[\frac{56}{3}\text{ }sq. unit\]
D) None of these
Correct Answer: B
Solution :
Required area = \[CDD'C'=2\times ABCD\] \[=2\int_{1}^{4}{\sqrt{2}}{{x}^{1/2}}\,dx=\frac{28\sqrt{2}}{3}\] sq. unit.You need to login to perform this action.
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