A) 1/6
B) 1/3
C) 5/6
D) 5/3
Correct Answer: B
Solution :
Required area = 2 (shaded area in first quadrant) =\[2\int_{0}^{1}{(x-{{x}^{2}})\,dx=2\times \frac{1}{6}=\frac{1}{3}}\].You need to login to perform this action.
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