A) \[\frac{16\pi }{3\sqrt{3}}\]
B) \[\frac{8\pi }{2\sqrt{3}}\]
C) \[\frac{24\pi }{3\sqrt{3}}\]
D) None of these
Correct Answer: A
Solution :
(a): (i) Circum radius\[=\frac{a}{\sqrt{3}}\]and in ? radius\[=\frac{a}{\sqrt{3}}\] Where ?a? is the side of the outer equilateral triangle. (ii) For an equilateral triangle of side a. if an in-circle and circum circle are drawn whose radii are r and R then \[r=\frac{a}{2\sqrt{3}}\] and \[R=\frac{a}{\sqrt{3}}\]
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