A) 25 \[c{{m}^{2}}\]
B) \[\frac{25}{2}\sqrt{2}\,c{{m}^{2}}\]
C) \[25\sqrt{2}\]\[c{{m}^{2}}\]
D) \[25\sqrt{3}\]\[c{{m}^{2}}\]
Correct Answer: C
Solution :
(c): \[AB=AC=10\]cm \[Area=\frac{1}{2}bc\,sinA=\frac{1}{2}\times 10\times 10\,sin{{45}^{{}^\circ }}\] \[=\frac{50}{\sqrt{2}}=\frac{50\times \sqrt{2}}{\sqrt{2}\times \sqrt{2}}=25\sqrt{2}\]\[c{{m}^{2}}\]You need to login to perform this action.
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