A) 4 units
B) \[2\sqrt{3}\]units
C) \[2\sqrt{2}\]units
D) \[3\sqrt{2}\]units
Correct Answer: C
Solution :
(c): Let, \[AB=AC=x\] units \[BD=DC=2\text{ }unit\text{ }\left[ \therefore BC=4\text{ }units \right]\] Now, \[AD=\sqrt{A{{B}^{2}}-B{{D}^{2}}}=\sqrt{{{x}^{2}}-1}\] \[\therefore \frac{4}{2}\times BC\times AD=8\] \[\Rightarrow \]\[\frac{1}{2}\times 4\times \sqrt{{{x}^{2}}-1}=8\Rightarrow \sqrt{{{x}^{2}}-1}=4\] \[\Rightarrow {{x}^{2}}-1=16\]\[\Rightarrow {{x}^{2}}=17\Rightarrow x=\sqrt{17}\]units
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