A) \[70\text{ }m\]
B) \[105\text{ }m\]
C) \[88\text{ }m\]
D) \[85\text{ }m\]
Correct Answer: C
Solution :
We have, \[AB=28\,m\,\,\Rightarrow \,AO=OB=14\,m\] Radius of semicircle with diameter AB (R) \[=\frac{28}{2}=14\,m\] Radius of semicircle with diameter AO \[({{r}_{1}})\] \[=\frac{14}{2}=7\,m\] Perimeter of shaded region \[=\pi R+\pi {{r}_{1}}+\pi {{r}_{1}}\] \[=\pi \,(14+7+7)=\frac{22}{7}\times 28=88\,m\]
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