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10th Class Mathematics Arithmetic Progressions Question Bank Arithmetic Progressions

  • question_answer
    A circle is divided into 18 sectors such that the angles subtended at the centre form an arithmetic progression. Given that the angle of the smallest sector is\[\text{11}.\text{5}{}^\circ \], find the angle of the biggest sector.

    A)  \[\text{3}0{}^\circ \]                                     

    B)  \[\text{15}.\text{5}{}^\circ \]

    C)  \[\text{45}{}^\circ \]                     

    D)         \[\text{28}.\text{5}{}^\circ \]

    Correct Answer: D

    Solution :

     Since \[\sqrt{9}-\sqrt{4}=3-2=1\]and d = 1. \[\sqrt{2}-\sqrt{3}\] \[1789=29x+49\] \['x'\]The angle of the biggest sector is \[\therefore \]


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