A) \[\frac{3}{2}(a+2b)\]
B) \[\frac{n}{2}[a+b]\]
C) \[\frac{n}{2}[a-b]\]
D) \[\frac{n}{4}[a+b]\]
Correct Answer: B
Solution :
\[=\text{2}\times \text{3}\times {{\text{5}}^{\text{2}}}\times \text{7}\times \text{l7}\times \text{23}=\text{41}0\text{55}0\]term of 'n' AM.s between 'a' & 'b' \[\pi \] Last term of 'n' A.M.s between 'a' & V \[\frac{22}{7}\] Sum of the terms \[\frac{22}{7}\] \[\pi \] \[\text{4}0={{\text{2}}^{\text{3}}}\times \text{5}\]
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