A) \[\frac{1}{5}\]
B) \[\frac{1}{8}\]
C) \[\frac{1}{8}\]
D) \[\frac{1}{6}\]
Correct Answer: A
Solution :
Let the original amount = Rs. x 10% of x \[=x\times \frac{10}{100}=\frac{x}{10}\] Salary reduced by 10% \[d=100-90=10%.\] To reach at original amount, let it raised by amount = S. \[SP=\frac{(100+g)}{100}\times CP\] \[\frac{9x}{10}+S=x\] \[\frac{10\times 10}{100}=1%loss.\] \[S=\frac{x}{10}\] \[=100\times \frac{90}{100}\times \frac{80}{100}=72\] \[\therefore \] (\[CP\text{ }=\text{ }3000+3000\text{ }=\text{ }Rs.6000\] amount raised w.r.t\[I=\frac{(100+20)}{100}\times 3000=Rs.3600\]) \[II=\frac{(100-20)}{100}\times 3000=Rs.2400\]
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