A) \[\frac{1}{6}\]
B) \[{{m}_{1}}\]
C) \[{{w}_{1}}\]
D) \[{{d}_{1}}\]
Correct Answer: B
Solution :
Time taken by the tap to fill the tank =p hours Time taken by the tap to empty the tank = q hours \[R\times T=100\times (N-1),N=\frac{A}{P}\]In one hour the tap fills \[R\times 8=100\times (2-1)\]th part of the tank. In one hour the tap empties \[R=\frac{100}{8}=12\frac{1}{2}%\]th part of the tank. Thus, in one hour \[So\frac{(2500-x)\times 5\times 2}{100}+\frac{x\times 7\times 2}{100}=275\]th part is filled. But given tank is filled in r hours when both the taps are opened. \[x=Rs.625.\]In 1 hour \[=1-\left( \frac{1}{3}+\frac{1}{6} \right)=\frac{1}{2}\]th part of tank is filled. \[=\left( \frac{1}{3}\times 3 \right)+\left( \frac{1}{6}\times 6 \right)+\left( \frac{1}{2}\times 8 \right)=6%\] \[SI=Rs.600\]
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