• # question_answer A boy walking at a speed of 10 km/hr reaches his school 15 minutes late. Next time his speed increase by 2 km/hr, but still he is late by 5 minutes. Find the distance of his school from his house.      A)  20 km             B)  30 kmC)  10 km             D)  5 km

Here, the difference in time$=155=10$ minutes $=\frac{1}{6}$ hours His speed during next journey$=10+2=12$ km/hr. $\therefore$Required distance$=\frac{12\times 10}{12-10}\times \frac{1}{6}=10\,\,km$