A) \[\frac{7}{15}\]
B) \[\frac{9}{17}\]
C) \[\frac{13}{26}\]
D) \[\frac{5}{8}\]
Correct Answer: C
Solution :
We compare given fractions with \[\frac{1}{2}\] and find that \[\frac{9}{17}>\frac{1}{2},\,\frac{13}{26}\,=\frac{1}{2}\,,\,\frac{7}{15}<\frac{1}{2},\,\frac{5}{8}>\frac{1}{2},\,\frac{3}{7}<\frac{1}{2}\] Two fractions are greater than \[\frac{1}{2},\] two are smaller than \[\frac{1}{2}\] and one fractions is equal to \[\frac{1}{2}\]\[\therefore \] While arranging given fractions in descending order of their values \[\frac{13}{26}\] comes in middle.
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