A) \[=P\left( 1+\frac{{{R}_{1}}}{100} \right)\times \left( 1+\frac{{{R}_{2}}}{100} \right).\]
B) \[=P{{\left( 1-\frac{R}{100} \right)}^{n}}.\]
C) 33
D) 30
Correct Answer: A
Solution :
Let B's salary be Rs.100, so A's salary is Rs.150. So % of B's salary less than A \[M.P.=\frac{100\times S.P.}{100-Discount%}\]
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