A) 24
B) 16
C) 32
D) 12
Correct Answer: A
Solution :
Let sum be Rs. x so amount Rs.2x. So S.I. = Rs. x, \[C.I.=P\left[ \left( 1+\frac{{{R}_{1}}}{100} \right)\left( 1+\frac{{{R}_{2}}}{100} \right)....\left( 1+\frac{{{R}_{n}}}{100} \right)-1 \right]\] \[5\frac{1}{4}\] Now, for amount = Rs. 4 x \[A=P{{\left( 1+\frac{R}{100} \right)}^{5}}\left( 1+\frac{\frac{R}{4}}{100} \right)\] \[{{V}_{0}}\]
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