A) 1.5 years
B) 3 years
C) 2 years
D) \[\frac{5}{2}\] years
Correct Answer: A
Solution :
Use \[18522=16000{{\left( 1+\frac{5}{100} \right)}^{n}}\] \[\frac{1}{y}=\frac{1}{x}+\frac{1}{100}\] \[Discount%=\frac{Discount}{M.P.}\times 100\] \[\text{-}\frac{\text{Discount }\!\!%\!\!\text{ }\!\!\times\!\!\text{ M}\text{.P}\text{.}}{\text{100}}\] \[S.P.=M.P.\times \left\{ 1-\frac{Discount%}{100} \right\}\] \[\text{S}\text{.P}\text{.=M}\text{.P}\text{. }\!\!\times\!\!\text{ }\left\{ \text{1-}\frac{\text{Discount }\!\!%\!\!\text{ }}{\text{100}} \right\}\]Time \[\text{S}\text{.P}\text{.=M}\text{.P}\text{. }\!\!\times\!\!\text{ }\left\{ \frac{\text{100 - Discount }\!\!%\!\!\text{ }}{\text{100}} \right\}\]
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