A) 2770 yrs
B) 2966 yrs
C) 2980 yrs
D) 3070 yrs
Correct Answer: B
Solution :
Given \[{{N}_{o}}=1,{{N}_{t}}=0.70\] and \[{{t}_{1/2}}=5760\] yrs. \[k=\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{5760}\] . We also know, \[k=\frac{2.303}{t}\]\[\log \frac{{{N}_{0}}}{{{N}_{t}}}.\frac{0.693}{5760}\] or \[t=\frac{2.303\times 5760\times 0.155}{0.693}=2966yrs.\]You need to login to perform this action.
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