A) Proton
B) Neutron
C) Alpha particle
D) Deuteron
Correct Answer: C
Solution :
\[_{13}A{{l}^{28}}+{{\,}_{2}}H{{e}^{4}}\to {{\,}_{15}}{{P}^{31}}+{{\,}_{0}}{{n}^{1}}\]You need to login to perform this action.
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