A) \[\frac{y}{2}\]
B) \[\frac{y}{4}\]
C) y
D) 2y
Correct Answer: C
Solution :
Number of moles of A\[=\frac{x}{40}\] Number of atoms of A\[=\frac{x}{40}\times \text{Avogadro}\ \text{no}\text{.}=y\](say) Or \[x=\frac{40y}{\text{Avogadro no}\text{.}}\] Number of moles of B\[=\frac{2x}{80}\] Number of atoms of B \[=\frac{2x}{80}\times \text{Av}\text{. no}\text{.}=\frac{2}{80}\times \frac{40y}{\text{Av}\text{. no}\text{.}}\times \text{Av}\text{. no}\text{.}=\text{y}\]
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