A) II<I<III<IV
B) IV<III<II<I
C) II<III<I<IV
D) III<IV<I<II
Correct Answer: A
Solution :
(I) 1 molecule of oxygen \[\because \] \[6\times {{10}^{23}}\] molecule has mass \[=32gm\] \[\therefore \] 1 molecule of \[{{O}_{2}}\] has mass \[=\frac{32}{6\times {{10}^{23}}}\] \[=5.3\times {{10}^{-23}}gm\] (II) 1 atom of nitrogen \[\because \] \[2\times 6\times {{10}^{23}}\]atoms of \[{{N}_{2}}\]has mass = 28gm \[\therefore \] 1 atom of \[{{N}_{2}}\]has mass \[=\frac{28}{2\times 6\times {{10}^{23}}}\] \[=2.3\times {{10}^{-23}}gm\] (III) \[1\times {{10}^{-10}}g\]molecular weight of oxygen g atomic weight \[=2\times 1\times {{10}^{-10}}=2\times {{10}^{-10}}g\] (IV) \[1\times {{10}^{-10}}g\]atomic weight of copper So, order of increasing masses \[\text{II}<\text{I}<\text{III}<\text{IV}\].
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