A) \[2\ g\] atom of nitrogen
B) \[3\times {{10}^{23}}\] atoms of \[C\]
C) 1 mole of \[S\]
D) \[7.0\ g\] of \[Ag\]
Correct Answer: B
Solution :
A. 2gm atom of nitrogen = 28gm B. \[6\times {{10}^{23}}\] atoms of C has mass \[=12gm\] \[3\times {{10}^{23}}\]atoms of C has mass \[=\frac{12\times 3\times {{10}^{23}}}{6\times {{10}^{23}}}=6gm\] C. 1mole of S has mass = 32gm D. 7.0gm of Ag So, lowest mass = 6gm of C.
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